Directions (Q. Nos.1 to 5) What will come in place of
question mark (?) in the following questions?
1. 348 ÷ 29 x 15
+ 156 = (?)3 + 120
(1) 12
(2)
6 (Ans)
(3) 36
(4) 9
(5) None of
these
Ans : 348 ÷ 29 x 15
+ 156 = (?)3 + 120
⇒ 12 x 15 + 156 = (?)3 + 120
⇒ 180 + 156 - 120 = (?)3
⇒
216 = (?)3
⇒
(6)3 = (?)3
∴
? = 6
2. (4 x 4)3
÷ (512 ÷ 8)4 x (32 x 8)4 = (2 x 2)? + 4
(1) 8
(2) 12
(3)
6 (Ans)
(4) 14
(5) None of
these
Ans : (4 x 4)3
÷ (512 ÷ 8)4 x (32 x 8)4 = (2 x 2)? + 4
⇒ (16)3 ÷ (64)4
x (256)4 = (4)? + 4
⇒ (4)2x3 ÷ (4)3x4
x (4)4x4 = (4)? + 4
⇒ (4)6 ÷ (4)12 x
(4)16 = (4)? + 4
⇒
(4)6-2+16 = (4)? + 4
⇒
(4)10 = (4)? + 4
⇒
10 = ? + 4
∴
? = 6
3. (2√392 - 21)
+ (√8 - 7)2 = (?)2
(1) 4
(2) -4
(3) 12
(4) 2
(5)
6 (Ans)
Ans : (2√392
- 21) + (√8 - 7)2 = (?)2
⇒
(2 x 14√2 - 21) + (√8 - 7)2 = (?)2
⇒ 28√2 - 21 + (√8)2 - 2 x √8 x 7
+ (7)2 = (?)2
⇒
28√2 - 21 + 8 - 28√2 + 49 = (?)2
⇒
- 21 + 8 + 49 = (?)2
⇒
36 = (?)2
∴ ? = 6
4. 1 1/4 + 1 1/6
- 1 1/8 = ? + 1 1/12
(1) 5/24
(Ans)
(2) 7/24
(3) 5/12
(4) 7/12
(5) None of
these
Ans : 1
1/4 + 1 1/6 - 1 1/8 = ? + 1 1/12
⇒
1 1/4 + 1 1/6 - 1 1/8 - 1 1/12 =
?
⇒ (1 + 1 - 1 - 1) + (1/4 + 1/6 - 1/8 - 1/12) = ?
⇒ 0 + (6 + 4 - 3 - 2/24) = ? ⇒
0 + 5/24 = ?
∴
? = 5/24
5. 76% of 1285 =
35% of 1256 + ?
(1) 543
(2)
537 (Ans)
(3) 547
(4) 533
(5) None of
these
Ans :
76% of 1285 = 35% of 1256 + ?
⇒
976.6 = 439.6 + ?
⇒ 976.6 - 439.6 = ?
∴
? = 537
Directions (Q. Nos. 6 to 10) What approximate value
will come in place of question mark (?)
in the following questions? (You are not expected to calculate the exact value)
Solutions (106 to 110)
You can take approximate value
of any number
6. 499.99 + 1999
÷ 39.99 x 50.01 = ?
(1) 3200
(2) 2700
(3) 3000
(Ans)
(4) 2500
(5) 2400
Ans :
499.99 + 1999 ÷ 39.99 x 50.01 = ?
500 + 2000 ÷
40 x 50 = ?
500 + 50 x 50 = ?
500 + 2500 = ?
3000 = ?
7. [(7.99)2
- (13.001)2 + '(4.01)3]2 = ?
(1) -1800
(2) 1450
(3) -1660
(4) 1660 (Ans)
(5) -1450
Ans :
[(7.99)2 - (13.001)2 + '(4.01)3]2 =
?
⇒
[(8)2 - (13)2 + (4)3]2 = ?
⇒
[64 - 169 + 64]2 = ?
⇒
(-41)2 = ?
∴
? = 1681 (∵- x - ⇒ +)
≈ 1660
8. 601/49 x
399/81 ÷ 29/201 = ?
(1) 520
(2) 360
(3) 460
(4) 500
(5) 420
(Ans)
Ans : 601/49
x 399/81 ÷ 29/201 = ?
⇒ 601/49 x 399/81 x
201/29 = ?
⇒ 600/50 x 400/80 x
200/30 = ?
∴ 400 = ?
420 ≈ ?
9. 441.01 -
232.99 + 1649.99 = ? + 1225.92
(1) 600
(2) 630
(Ans)
(3) 660
(4) 690
(5) 720
Ans : 441.01
- 232.99 + 1649.99 = ? + 1225.92
⇒ 441 - 233 +
1650 - 1226 = ?
⇒
2091 - 1459 = ?
∴
? = 623 ≈ 630
10. (21.5% of
999)1/3 + (43% of 601)1/2 = ?
(1) 18
(2) 22
(Ans)
(3) 26
(4) 30
(5) 33
Ans : (21.5%
of 999)1/3 + (43% of 601)1/2 = ?
(1000 X 21.5%)1/3 + (600 X 43%)1/2 = ?
(215)1/3 + (258)1/2 = ?
(216)1/3 + (256)1/2 = ?
(6)3X1/3 + (16)2X1/2 = ?
6 + 16 = ?
22 = ?
Directions (Q. Nos. 11 to 15) What will come in place of
question mark (?) in the following number series?
11. 15
21 39 77 143 (?)
(1) 243
(2) 240
(3) 253
(4) 245
(5) None of
these (Ans)
Ans :
- Solutions - Qn Ans -111
12. 33
39 57 87 129 (?)8
(1) 183
(Ans)
(2) 177
(3) 189
(4) 199
(5)
Ans :
Solutions - Qn Ans -112
13. 15
19 83 119 631 (?)
(1) 731
(Ans)
(2) 693
(3) 712
(4) 683
(5) None of
these
Ans : Solutions -
Qn Ans -113
14. 19
26 40 68 124 (?)
(1) 246
(2) 238
(3) 236
(Ans)
(4) 256
(5) None of
these
Ans : Solutions
- Qn Ans -114
15. 43
69 58 84 73 (?)
(1) 62
(2) 98
(3) 109
(4) 63
(5) None of
these (Ans)
Ans : Solutions - Qn
Ans -115
Directions (Q. Nos. 16 to 20) In the following questions, two
equations numbered I and II are given. You have to solve both the equations and
give answer
(1) if x
> y
(2) if x ≥ y
(3) if x <
y
(4) if x ≤ y
(5) if x = y
or the relationship cannot be established
Ans :
16. I.
x2 - 11x + 24 = 0
II. 2y2 - 9y + 9 = 0
Ans : 2
I. x2 - 11x + 24 = 0
x2 - 8x - 3x + 24 = 0
x (x - 8) - 3 (x - 8) = 0
(x - 8)(x - 3) = 0
∴ x = 8 or 3
II.
2y2 - 9y + 9 = 0
2y2 - 6y - 3y + 9 = 0
2y(y -
3) - 3 (y - 3) = 0
(2y - 3) (y - 3) = 0
∴ y = 3/2 or 3
So,
x ≥ y
17. I.
x3 * 13 = x2 * 247
II. y1/3 * 14 = 294 ÷ y2/3
Ans : 3
I. x3 * 13 = x2 * 247
or x3
/ x2 = 247/13
x = 19
II.
y1/3 * 14 = 294 ÷ y2/3
or,
(y)1/3 * (y)2/3 = 294/14
or,
(y)1/3+2/3 = 21
∴
y = 21
So,
y > x
18. I. 12 * 4 / x4/7 - 3 * 4 / x4/7
= x10/7
II. y3 + 783 = 999
Ans : 4 I. 12 * 4
/ x4/7 - 3 * 4 / x4/7 = x10/7
or,
48 - 12 = (x)10/7 * (x)4/7
or,
36 = (x)7 = (x)2
∴
x = ±6
II.
y3 + 783 = 999
y3 = 999 - 783
y3 = 216
∴
y = ±6
∴
y ≥ x
19. I. √500 x + √402 = 0
II. √360 y + (200)1/2 = 0
Ans : 5
I. √500 x + √402 = 0
or,
√500 x = - √402
By squaring
both sides, we get
500 x2 = 402
x = √402 /500 = ± 0.897
II. √360
y + (200)1/2 = 0
or,
(200)1/2 = - √360 y
By squaring
both sides, we get
Solutions
- Qn Ans -119 = (-√360 y)2
200 = 360 y2
y = √200/360 = ± 0.75
relationship
cannot established.
20. I. (17)2 + 114 ÷ 18 = x
II. (26)2 - 18 * 21 = y
Ans : 3
I. (17)2 + 114 ÷ 18 = x
289 + 8 = x
∴
x = 297
II. (26)2 - 18 * 21 = y
676 - 378 = y
∴
298 = y
So,
y > x
21. The
respective ratio between the present age of Ram and Rakesh is 6 : 11. Four
years ago, the ratio of their ages was 1 : 2 respectively. What will be
Rakesh's age after five years?
(1) 45
years
(2) 29 years
(3) 49 years
(Ans)
(4) Cannot be
determined
(5) None of
these
Ans : Let the age of Ram = x and
Rakesh = y then x/y = 6/11
∴ x = 6y/11
According to
question, x - 4/y - 4 = 1/2
2x - 8 = y - 4
2 * 6y/11 - 8 = y - 4
12y/11 - y = - 4 + 8
y/11 = 4
∴
y = 44 yr
∴ Age of Rakesh after 5 yr
= 44 + 5 = 49 yr
22. The
circumference of two circles is 83 m and 220 m respectively. What is the
difference between the area of the larger circle and the smaller circle?
(1) 3422
sq m
(2) 3242 sq m
(3) 3244 sp m
(4) 3424 sq m
(5) None of
these (Ans)
Ans : 2 π r = 88
∴
r = 88 * 7/44 = 14 m
∴
Area = π r2
= 22/7 * 14 * 14
= 616 m2
2π r1 = 220
r1 = 220 * 7/2 * 22 = 35 m
∴ Area = π r12 = 22/7 * 35 * 35 =
3850 m2
Difference = 3850 -
616 = 3234 m2
23. One of the
angles of a triangle is two-third angle of sum of adjacent angles of
parallelogram. Remaining angles of the triangle are in ratio 5 : 7
respectively. What is the value of second largest angle of the triangle?
(1) 250
(2) 400
(3) 350
(Ans)
(4) Cannot be
determined
(5) None of
these
Ans : An angle of a triangle =
2/3 * 1800 = 1200
Remaining 1800 - 1200
= 600 is the ratio of 5 : 7.
So,
5x + 7x = 60
12x = 60
x = 5
So, angles are 5 * 5 = 250
and 7 * 5 = 350
and
1200
So, value of second largest
angle of triangle is 350 .
24. Pradeep
invested 20% more than Mohit. Mohit invested 10% less than Raghu. If the total
sum of their investment is Rs. 17880, how much amount did Raghu invest?
(1) Rs.6000
(Ans)
(2) Rs.8000
(3) Rs.7000
(4) Rs.5000
(5) None of
these
Ans : Let the investment by
Raghu = x
then Mohit = x * 90/100 = 9x/10
Pradeep = 9x/10 * 120/100 =
108x/100
According to question, x +
9x/10 + 108x/100 = 17880
100x + 90x + 108x/100 = 17880
298x/100 = 17880
x = 6000
25. Average score
of Rahul, Manish and Suresh is 63. Rahul's score is 15 less than Ajay and 10
more than the average scores of Rahul, Manish and Suresh, what is he sum of
Manish's and Suresh's scores ?
(1) 120
(2) 111
(Ans)
(3) 117
(4) Cannot be
determined
(5) None of
these
Ans : Let the score of Ajay = x
Rahul
= x - 15
Manish = x -
25
According to question, x = 63 +
30
∴
x = 93
∴ Score of
Ajay = 93
then
Rahul
= 93 - 15 =78
then
Manish
= 93 - 25 = 68
Total marks of Rahul, Manish
and Suresh = 3 * 63 = 189
∴ Suresh = 189 - (78 + 68) = 43
∴ Manish + Suresh = 68 + 43 = 111
26. Fifty-three
per cent of a number is 358 less than the square of 26. What is the value of
three-fourth of 23 per cent of that number?
(1) 101
(2) 109.5
(3) 113
(4) 103.5 (Ans)
(5) None of
these
Ans : (26)2 - 358 = x *
53/100
318 = x * 53/100
∴
x = 600
Again 600 * 3/4 * 23/100 =
103.5
27. The average
speed of a car is 1 4/5 times the average speed of a bus. A tractor covers 575
km in 23 hours. How much distance will the car cover in 4 hours if the
speed of the bus is twice speed of the tractor?
(1) 340
km
(2) 480 km
(3) 360 km (Ans)
(4) 450 km
(5) None of
these
Ans : Average speed of a tractor
=575/23 = 25 km/h
The speed of a bus in an hour =
25 * 2 = 50 km
The speed of a car in an hour =
50 * 9/5 = 90 km
So, the distance covered by car
in 4 h is
90 * 4 = 360 km
28. The simple
interest accrued on a sum of certain principal is Rs.2000 in five years at the
rate of 4% per annum. What would be the compound interest accrued on same
principal at same rate in two years?
(1) Rs.716
(2) Rs.724
(3) Rs.824
(4) Rs.816
(Ans)
(5) None of
these
Ans : 2000 = P * 4 * 5/100
∴ P = 10000
Now,
CI = 10000[(1 + 4/100)2 - 1]
= 10000 * 0.0816
= 816
29. Rehaan purchased a bike for Rs.54000. He sold it at a loss of 8 per cent. With that money he again purchased another bike and sold it at a profit of 10 per cent. What is his overall loss/profit?
(1) Loss
of Rs.657
(2) Profit of
Rs.567
(3) Loss of
Rs.648
(4) Profit of
Rs.648 (Ans)
(5) None of
these
Ans : Cost price = 54000
Selling price = 54000 *
(100-8)/100 = 49680
Now, the cost price of another
bike = 49680
Selling price of another bike =
49680 * 110/100 = 54648
Overall profit = 54648 - 54000
= 648
30. Two men alone
or three women alone can complete a piece of work in 4 days. In how many days
can one woman and one man together complete the same piece of work?
(1) 6
days
(2) 24/5
days (Ans)
(3) 12/1.75
days
(4) Cannot be
determined
(5) None of
these
Ans : 2M = 3W
∴ 1M = 3/2 W
∴ 1M + 1W = 3/2 W + 1W = 5/2 W
Number of days = 3 * 4/5/2 =
24/5 days
Directions (Q. Nos. 31 to 35) Study the table carefully to
answer the questions that follow
Number of employees working in
four different companies in five different years
Year
|
Company
|
|||||||
A
|
B
|
C
|
D
|
|||||
Male
|
Female
|
Male
|
Female
|
Male
|
Female
|
Male
|
Female
|
|
2004
2005 2006 2007 2008 |
200
250 400 650 750 |
400
150 250 400 300 |
250
400 850 500 600 |
450
100 400 150 350 |
350
550 350 650 400 |
600
350 500 500 300 |
400
550 650 700 650 |
450
600 450 600 400 |
31. What was the
total number of males working in Company-A in the year 2007, males working in
Company-B in the year 2005 and females working in Company-D in the year 2006
together?
(1) 1550
(2) 1600
(3) 1450
(4) 1400
(5) None of
these (Ans)
Ans : Required number
= 650 + 400 + 450 = 1500
32. What was the
average number of female employees working in all the companies together in the
year 2004?
(1) 475
(Ans)
(2) 385
(3) 450
(4) 300
(5) None of
these
Ans : Average = 400 + 450 + 600 +
450/4
= 1900/4 = 475
33. Total number
of male employees working in Company-C over all the years together was
approximately what percentage of total number of employees working in the year
2007 in all the companies together?
(1) 41
(2) 46
(3) 51
(4)
55 (Ans)
(5) 59
Ans : Total number of male employees
working in company. C over all the years together
= 350 + 550 + 350 + 650 + 400 =
2300
Total number of employees
working in the companies in the year 2007 together
= 650 + 400+ 500 + 150 + 650 +
500 + 700 + 600 = 4150
Required percentage = 2300/4150
* 100
≈ 55%
34. If 20 per
cent of male and 30 per cent of female employees in Company-B in the year 2004
were handicapped, then what was the total number of handicapped candidates in
that company in that year?
(1) 185
(Ans)
(2) 170
(3) 190
(4) 195
(5) None of
these
Ans : Handicapped employees in
company. B in the year 2004
= 250 * 20/100 + 450 * 30/100
= 50 + 135 = 185
35. What was the respective ratio between the number of males in Company-D in the year 2005, number of females in Company-A in the year 2006 and the number of males in Company-B in the year 2005?
(1) 11 :
5 : 8 (Ans)
(2) 11 : 6 : 8
(3) 12 : 5 : 9
(4) 12 : 5 : 7
(5) 11 : 5 : 9
Ans : Ratio = 550 : 250 : 400
= 11 : 5 :
8
(Dividing by 50 to all)
Directions (Q. Nos. 36 to 40) Study the following table
carefully to answer the questions that follow:
Monthly rent (in Rs. thousands)
at five different places in six different years
Year
|
Place
|
||||
Church-gate
|
Dadar
|
Kandivali
|
Borivali
|
Virar
|
|
2005
2006
2007
2008
2009
2010
|
5.3
12.5
16.7
20.9
25.8
30.3
|
3.8
8.3
11.7
13.6
14.5
20.9
|
1.5
3.4
5.5
9.8
11.5
15.6
|
2.7
4.8
6.6
12.7
14.1
15.9
|
1.1
2.1
1.8
3.6
5.5
7.8
|
36. In which
place, the monthly rent did not increase consistently from year 2005 to 2010?
(1) Churchgate
(2) Dadar
(3) Kandivali
(4) Borivali
(5)
Virar (Ans)
37. In which year
at Churchgate, the monthly rent increased more than 100% from the previous
year?
(1) 2006 (Ans)
(2) 2007
(3) 2008
(4) 2009
(5) 2010
Ans : 2006 [12.5 - 5.3/5.3 *
100 = 135.85%]
38. What was the
difference between the monthly rent at Dadar in the year 2009 and Borivali in
the year 2007?
(1) Rs.
7600
(2) Rs. 7900 (Ans)
(3) Rs. 8100
(4) Rs. 8600
(5) None of
these
Ans : Required difference =
(14.5 - 6.6) 1000 = 7900
39. Monthly rent
at Kandivali in the year 2008 was approximately what per cent of the total
montly rent at Virar over all the years together?
(1) 30
(2) 33
(3) 38
(4) 42
(5) 45 (Ans)
Ans : Required percentage
=
9.8 *
100
≈ 45%
1.1 + 2.1 + 1.8 + 3.6 + 5.5+ 7.8
1.1 + 2.1 + 1.8 + 3.6 + 5.5+ 7.8
40. Which city
was most expensive in terms of rent?
(1) Churchgate
(Ans)
(2) Dadar
(3) Kandivali
(4) Borivali
(5)
Virar
Ans : Because of highest average
among all.
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